Question

plz find the value of x​

Answer 1

Answer:

value of x is

-31.......

Answer 2

Step-by-step explanation:

Question:-

$\sf \dfrac{x - 1}{2} - \dfrac{x - 2}{3} = \dfrac{x - 4}{7}$

To Find:-

• The value of x

Solution:-

$\sf \dashrightarrow \dfrac{x - 1}{2} - \dfrac{x - 2}{3} = \dfrac{x - 4}{7}$

$\sf\dashrightarrow \dfrac{3(x - 1) - 2(x - 2)}{6} = \dfrac{x - 4}{7}$

$\sf \dashrightarrow \dfrac{3x - 3- 2x + 4}{6} = \dfrac{x - 4}{7}$

$\sf \dashrightarrow \dfrac{3x - 2x + 4 - 3}{6} = \dfrac{x - 4}{7}$

$\sf \dashrightarrow \dfrac{x + 1}{6} = \dfrac{x - 4}{7}$

$\sf By \: cross \: multiplication:-$

$\sf \dashrightarrow7(x + 1)= 6(x - 4)$

$\sf \dashrightarrow7x + 7= 6x - 24$

$\sf \dashrightarrow7x - 6x= - 24 - 7$

$\dashrightarrow \underline{\boxed{\sf x= - 31}}$

$\underline {\sf Let's \: check:-}$

$\sf \dashrightarrow \dfrac{x - 1}{2} - \dfrac{x - 2}{3} = \dfrac{x - 4}{7}$

$\sf Substitute \: x = -31$

$\sf \dashrightarrow \dfrac{-31 - 1}{2} - \dfrac{-31 - 2}{3} = \dfrac{-31 - 4}{7}$

$\sf \dashrightarrow \dfrac{-32}{2} + \dfrac{33}{3} = \dfrac{-35}{7}$

$\sf \dashrightarrow -16 + 11 = -5$

$\sf \dashrightarrow -5 = -5$

LHS = RHS

Hence, Verified