plz friends prove it of trigonometry very urgent
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Step-by-step explanation:
cosα.sinα
sain2α
and this is the formula of
sim2α
Answered by
1
Step-by-step explanation:
sin(90°- x)*cos(90°-x)
=(sin90°*cosx - cos90°*sinx) (cos90°*cosx + sin90°*sinx)
= (1*cosx - 0*sinx)(0*cosx + 1*sinx)
= (cosx - 0)(0 + sinx)
= cosx * sinx
= sinx*cosx
= 2sinx*cosx/2
= sin2x/2
(sin2x = 2tanx /1+tan²x)
= 1/2 (2tanx/1+tan²x)
= tanx/1+tan²x
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