plz frnds solve this question
Attachments:
nitthesh7:
It is 2sinACosA
Answers
Answered by
0
Tan A / (1+Tan²A) + Cot A / (1+Cot²A) = 2(Sin A × Cos A)
Taking LHS
= Tan A / Sec²A + Cot A / Cosec²A
(because 1+Tan²A = Sec²A ; 1+Cot²A = Cosec²A)
= (Sin A / Cos A) × Cos²A + (Cos A / Sin A) × Sin²A
(because Tan A = Sin A / Cos A and Cot A = Cos A /Sin A)
(also Sec²A = 1/Cos²A and Cosec²A = 1/Sin²A)
= Sin A Cos A + Sin A Cos A
= 2 Sin A Cos A = RHS
Hence Proved.
_______________________________________________________
☺ ☺ ☺ Hope this Helps ☺ ☺ ☺
Taking LHS
= Tan A / Sec²A + Cot A / Cosec²A
(because 1+Tan²A = Sec²A ; 1+Cot²A = Cosec²A)
= (Sin A / Cos A) × Cos²A + (Cos A / Sin A) × Sin²A
(because Tan A = Sin A / Cos A and Cot A = Cos A /Sin A)
(also Sec²A = 1/Cos²A and Cosec²A = 1/Sin²A)
= Sin A Cos A + Sin A Cos A
= 2 Sin A Cos A = RHS
Hence Proved.
_______________________________________________________
☺ ☺ ☺ Hope this Helps ☺ ☺ ☺
Similar questions
English,
8 months ago
Computer Science,
8 months ago
Hindi,
8 months ago
Science,
1 year ago
Social Sciences,
1 year ago
Hindi,
1 year ago
Economy,
1 year ago
Social Sciences,
1 year ago