Math, asked by sagar4864, 11 months ago

plz from exponents and powers chapter​

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Answered by RvChaudharY50
63

\Large\underline\mathfrak{Question}

Solve The Following :-----

\large\boxed{\bold{ \frac{5^{ - 3}  \times  {6}^{2} \times  {7}^{ - 3}  }{12 ^{4}  \times 125 \times  {49}^{2} } }}

\Large\bold\star\underline{\underline\textbf{Formula\:used}}

  • a^(-n) = 1/a^n
  • (a^b)/(a^c) = a^(b-c)
  • a^b×a^c = a^(b+c)
  • (a×b)^n = a^n×b^n

__________________

\Large\underline{\underline{\sf{Solution}:}}

First let simply some things :---

→ 5^(-3) = 1/5³

→ 7^(-3) = 1/7³

→ (12)⁴ = (2×6)⁴ = 2⁴ × 6⁴

→ 49² = ((7)²)² = 7⁴

→ 125 = 5³

Putting all these Now in Question we get :-----

 \red \leadsto \:  \purple{\frac{ {6}^{2} }{ {2}^{4} \times  {6}^{4} \times  {6}^{ - 2}  \times  {5}^{3}  \times  {5}^{3} \times  {7}^{4}  \times  {7}^{3}}} \\  \\  \red \leadsto \:  \frac{ {6}^{2} }{ {2}^{4}  \times  {6}^{(4 - 2)} \times  {5}^{(3 + 3)}  \times  {7}^{(4 + 3)}  }  \\  \\  \red \leadsto \:  \pink{ \frac{ {6}^{2} }{ {2}^{4}  \times  {6}^{2} \times  {5}^{6}  \times  {7}^{7}  }} \\  \\ \red \leadsto  \:  \red{\large\boxed{\bold{ \frac{1}{ {2}^{4}  \times  {5}^{6}  \times  {7}^{7} } }}}

\large\underline\textbf{Hope it Helps You.}

Answered by Anonymous
8

Answer:

6²/2⁴×6⁴×6^-2×5³×5³×7⁴

6²/2⁴×6(4-2)×5^5+5×7^7

6²/2⁴×6²×5^6×7^7

1/2⁴×5^6×7^7

Step-by-step explanation:

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