Question

plz gie th ans of part 5​

Answer 1

3x^2 - 1 can be written as (3x+1)(3x-1) {identity}

x = -1/3 and +1/3

3x^2 - 1 can be written as 3x^2 + 0x - 1

$\alpha + \beta = \frac{ - b }{a}$

= 0/3 = 9

$\alpha \beta = \frac{c}{a}$

= -1/3