Question

plz give a detail answer of this question

Answer 1

time of ascent = 2 sec
height = u^2 / 2g
:: v = u + at
0 = u +(-10)2
::: u = 20 m/s
=====》 h = 400 / 2 × 10
:::::::》 height = 20 m
THE BALL WILL RISE TO A HEIGHT OF 2O M.




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