Math, asked by chhotu81, 1 year ago

plz give a quick answer

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Answered by Anonymous

Please see the images

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chhotu81: plz give the comlete answer

chhotu81: in image the answer is not complete

Anonymous: There are 3 images attached

Anonymous: chottu , 3 chai

chhotu81: other two images are not seen

Anonymous: can u see it now

Anonymous: they are there only

chhotu81: yes, there is only image here

Answered by Sanketh1

$as \: we \: know \: that \: in \: a \: circle \: when \: two \: tangents \: are \: drawn \: from \: a \: point \: they \: are \: equal \: and \: posses \: equal \: angle \: to \: the \: centre \: o \: with \: angle \: opq = angle \: oqp$
then in triangle POQ angle OPQ +angle OQP+angle POQ=180°---------(1)
then in quadrilateral POQT angle PTQ+angle POQ= 180°------(2)
now from (1) and (2)
angle OPQ +angle OQP= angle PTQ
as we saw above that angles opposite to equal sides are equal.
Therefore angle OPQ+ angle OPQ= angle PTQ
2angle OPQ = angle PTQ

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