Question

PLZ GIVE A RIGHT ANSWER
plz tell that can we solve question 6 by distance formula as it is aparallelogram so opposites must be equal

Answer 1

On solving
${(3 - x)}^{2} - {(y - 2)}^{2} = 8 \\ 9 + {x}^{2} - 6x - {y}^{2} - 4 + 4y = 8 \\ {x}^{2} - {y}^{2} - 6x + 4y = 3 - - - - - (1) \\ \\ other \: one \\ \: 13 = {(x - 4)}^{2} + {(6 - y)}^{2} \\ {x}^{2} + 16 - 8x + {y}^{2} + 36 - 12y = 13 \\ {x}^{2} + {y}^{2} - 12y - 8x = 39 - - - - (2) \\ now \\ from \: eq(2) \\ we \: get \: \\ {x}^{2} - {y}^{2} = 39 + 8x + 12y \\ put \: this \: in \: eq.1 \\ so \\ 39 + 8x + 12y - 6x + 4y = 3 \\ 2x + 16y = - 36 \\ x = - 18 - 8y \\ now \: put \: value \: of \: x \: in \: any \: of \: the \: equation \: you \: will \: get \: answer$