Math, asked by yarti6527, 3 months ago

plz give ans ???????​

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Answers

Answered by Anonymous
1

Solution:-

Using quadratic formula

 \to \rm \:  {x}^{2}  - 3x + 7 = 0

so compare with

 \rm \to \: a {x}^{2}  + bx + c = 0

So

 \rm \: a = 1,b =  - 3 \:  \: and \: c = 7

Quadratic formula

 \rm \: x =  \dfrac{ - b \pm \sqrt{ {b}^{2}  - 4ac}  }{2a}

Put the value on formula

 \rm \: x =  \dfrac{9 \pm \sqrt{9 - 28} }{2}

 \rm x =  \dfrac{9 \pm \sqrt{ - 19} }{2}

This quadratic equation is not defined because as we know that those negative numbers which are present in square root is not defined

More about quadratic equation

Quadratic equations are the polynomial equations of degree 2 in one variable of type f(x) = ax2 + bx + c where a, b, c, ∈ R and a ≠ 0.

It is the general form of a quadratic equation where ‘a’ is called the leading coefficient and ‘c’ is called the absolute term of f (x).

The values of x satisfying the quadratic equation are the roots of the quadratic equation (α,β).

The quadratic equation will always have two roots. The nature of roots may be either real or imaginary.

A quadratic polynomial, when equated to zero, becomes a quadratic equation. The values of x satisfying the equation are called the roots of the quadratic equation.

General from: ax² + bx + c = 0

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