Question

plz give ans of the above mentioned question

Answer 1

x∧2+ax+a∧2+6a<0

∀x∈(1,2)

let x=1
1+a+a∧2+6a<0
a∧2+7a<-1

now let a=1
1+7=8 not less than -1
let a =-1
1-7=-6<-1
similarly for -2, -3 , -4 ,-5,-6 it holds
but when a =-7
49-49=0 not less than -1
 similarly for a=2
4+2a+a∧2+6a<0
a∧2+8a<-4
we find it holds true a=-1 till a=-7

so a value lie between -1 and -6

sum of squares of integral value=1+4+9+16+25+36
=91