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70 and 110
Step-by-step explanation:
Let ABCD is a parallelogram.
Now, ∠CBX = 110°
Now, ∠CBX and ∠CBA form a linear pair.
∠CBX + ∠CBA = 180°
⇒110° + ∠CBA = 180°
⇒∠CBA = 70°
Now, ∠BAD + ∠CBA = 180°
[adjacent angles of parallelogram are supplementary]
⇒∠BAD + 70° = 180°
⇒∠BAD = 110°
Now, ∠BCD = ∠BAD = 110°
[Opposite angles of∥gm are supplementary]
Now, ∠ADC = ∠CBA = 70°
[Opposite angles of∥gm are supplementary]
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