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If the number 6n, for any n, were to end with the digit 0, then it would be divisible by 5. That is, prime factorisation of 6n would contain thr prime 5. This is not possible because 6n= (2×3)n; so the only prime in the factorisation of 6n is 2 and 3. So, the uniqueness of fundamental theorem of Arithmetic guarantees that there are no other primes in the factorisation of 6n. So, there is no natural no. n for which 6n ends with the digit zero.
sahilostwal11:
which book u refer
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