Question

plz give answer fast but don't spam​

Answer 1

Answer:

ok dear wait i will done it on paper

Answer 2

Answer:

$given \\ 3x - 5y - 19 = 0 \\ = > 3x - 5y = 19 \\ = > 5y = 3x - 19 \\ = > y = \frac{3x - 19}{5} .......(1) \\ also \\ - 7x + 3y + 1 = 0 \\ = > - 7x + 3 y = 1..... ..(2) \\ putting(1)in(2) \\ = > - 7x + 3( \frac{3x - 19}{5} ) = 1 \\ = > - 7x + \frac{9x - 57}{5} = 1 \\ = > \frac{ - 35x + 9x - 57}{5} = 1 \\ = > - 26x - 57 = 5 \\ = > - 26x = 5 + 57 \\ = > x = \frac{62}{ - 26}$

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