plz give answer fast with details
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Answer:
X^2+X-6
X^2+(3-2)X-6
X^2+3X-2X-6
X(X+3)-2(X+3)
(X-2)(X+3)
so 2and 3 are the zeros of p(X)
Answered by
1
Step-by-step explanation:
x² + x - 6
x² + 3x - 2x - 6
x ( x + 3 ) - 2 ( x + 3 )
( x - 2) ( x + 3)
Than,
x - 2 = 0
x = 2
or,
x + 3 = 0
x = - 3
Hence,
( 2 , -3 ) is right answer....mark as brainliest
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