Math, asked by RanjanRaju, 9 months ago

plz give answer fast with details​

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Answered by anchalvarshney2468
0

Answer:

X^2+X-6

X^2+(3-2)X-6

X^2+3X-2X-6

X(X+3)-2(X+3)

(X-2)(X+3)

so 2and 3 are the zeros of p(X)

Answered by avitaylor101
1

Step-by-step explanation:

x² + x - 6

+ 3x - 2x - 6

x ( x + 3 ) - 2 ( x + 3 )

( x - 2) ( x + 3)

Than,

x - 2 = 0

x = 2

or,

x + 3 = 0

x = - 3

Hence,

( 2 , -3 ) is right answer....mark as brainliest

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