Question

Plz give answer in step by step explanation plz...I will give BRAINLIEST to correct answer...

Answer 1

Given ,

∆DEF 's <DEF = 39°

<DFE = 61°

So, <EDF = 180° - 39° - 61°

= 180° - 100°

= 80°

And <CDA = 180° - <EDF

= 180° - 80°

= 100°

In ∆ACD 's

<ACD = 52°

<ADC = 80°

So,. <CAD = 180° - 52° - 80°

= 180° - 132°

= 48°