Question

plz .....give answer...need it urgently​

Answer 1

Answer:

1

Step-by-step explanation:

in ∆ABC

A + B + C = 180

A = 180 - (B +C)

A/2 = 90- (B+C)/2

similarly,

B/2 = 90- (A+C)/2

and , C/2 = 90-(A+B )/2

now ,

cos(B+C)/2 ×cos (C+A)/2 × cos (A+B)/2

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sinA/2×sin B/2 × sin C/2

=) sin(90-(B+C)/2)×sin(90-(C+A)/2)×sin(90-(A+B)/2)

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sin A/2×sin B/2 × sin C/2

=) sinA/2 × sin B/2 × Sin C/2

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sin A/2×sin B/2 × sin C/2

=)1