Question

plz give answer of this question

Answer 1

this is correct answer of your questions

Answer 2

aloha!!

>>---------☺️---------<<
thank you so much for asking this question!!
here is your answer:

=> see picture attached for help.

given: a circle with tangents from a external point P.
construction: join O and P. join O and A. Join O and B.
to prove: AP = PB
proof:
we know that the tangents make 90° angle with the radius of the circle. ------(1)
so,

angle PAO = 90°
angle PBO = 90°

now we get two triangles.
now in ∆ APO and ∆ POB

OP = OP ( common )
angle PAO = angle PBO ( from 1 )
OA = OB ( radii)


now, ∆ APO is congruent to ∆ POB by RHS criteria.
so by CPCT,
AP = PB

=> tangents are equal.
hence proved.

>>-------☺️-------<<

hope it helps :^)