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1
1
=
5−
21
2
=
(5−
21
)(5+
21
)
2(5+
21
)
=
4
2(5+
21
)
⇒
x
1
=
2
5+
21
Now, x+
x
1
=
2
5−
21
+
2
5+
21
=5
Similarly, x
2
+
x
2
1
=(
2
5−
21
)
2
+(
2
5+
21
)
2
Using equation (1) we can easily write
x
2
+
x
2
1
=2×(
4
25
+
4
21
)=23
Also, x
3
+
x
3
1
=(
2
5−
21
)
3
+(
2
5+
21
)
3
Using equation (2),
x
3
+
x
3
1
=2×
2
5
×(
4
25
+
4
63
)=110
∴ (x
3
+
x
3
1
)−5(x
2
+
x
2
1
)+(x+
x
1
)=110−5×23+5=115−115=0
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