Question

plz give correct ans . i will make a brain..

Answer 1

Answer:

0

Step-by-step explanation:

logX + logY = log (XY)

= log (a2/bc) + log (b2/ac) + log (c2/ab)

= log (a2 b2 c2 / bcacab)

= log (a2 b2c2 / a2b2c2)

= log 1

= 0

Answer 2

Question :-

$log( \frac{ab}{cd} ) =?$

Solution :-

We know that -

Log (x/y) = Log x - Log y

Hence,

Log (ab/cd) = Log ab - Log cd

& we also know that -

Log xy = Log x + Log y

Hence,

Log ab - Log cd = Log a + Log b - ( Log c + Log d)

Log ab - Log cd = (Log a + Log b - Log c - Log d) Ans.