Math, asked by Anonymous, 6 months ago

plz give correct ans plz​

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Answered by DevyaniKhushi
1

Here,

 =  >  \rm \frac{ {p}^{2}  + 1 }{p}  = 2p \\  \\  =  >   \rm{p}^{2}  + 1 = 2p \times (p) \\  =  >  \rm {p}^{2}  + 1 =  {2p}^{2}  \\  =  > \rm  {p}^{2}  -  {2p}^{2}  + 1 = 0 \\   =  > \rm { - p}^{2}  + 1 = 0

As,

  • Its highest power is 2
  • It has a non-zero & non-negative exponent of variable.

Thus, It is a quadratic equation.

Answered by Anonymous
2

ʏᴇs, ɪᴛ ɪs ǫᴜᴀᴅʀᴀᴛɪᴄ ᴇǫᴜᴀᴛɪᴏɴ

ᴇxᴘʟᴀɪɴᴀᴛɪᴏɴ:

p²+1/p = 2p

p² + 1 = 2p²

1 = 2p² - p²

1 = p²

p² - 1 = 0

this is of the form ax² + bx + c

so, the given equation is a quadratic equation

hope it helps....

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