Math, asked by mayam23, 1 year ago

plz give correct answer.
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Answered by siddhartharao77
1

Answer:

30 hours

Step-by-step explanation:

(i)

Given that Pipe A can empty a tank in 5 hours.

Part emptied in 1 hour = (1/5).


(ii)

Given that Pipe B can empty a tank in 6 hours.

Part emptied in 1-hour = (1/6).


Given that they both are opened at the same time.

Net part filled in 1 hour = (1/5 - 1/6)

                                      = (6 - 5)/30

                                      = 1/30.


Therefore, tank is filled in 30 hours.


Hope it helps!

Answered by Grimmjow
1

Let the Capacity of the Tank to be filled be : T

Given : Pipe A can fill the Empty Tank in 5 Hours

\bf{\implies In\;One\;Hour,\;Pipe\;A\;can\;fill\;(\frac{T}{5})th\;of\;the\;Tank}

Given : Pipe B can empty the Full Tank in 6 Hours

\bf{\implies In\;One\;Hour,\;Pipe\;B\;can\;empty\;(\frac{T}{6})th\;of\;the\;Tank}

If Both Tanks are Opened at the same time :

\bf{\implies In\;One\;Hour,\;The\;Tank\;is\;filled\;by : (\frac{T}{5} - \frac{T}{6})}

\bf{\implies In\;One\;Hour,\;The\;Tank\;is\;filled\;by : (\frac{6T - 5T}{30})}

\bf{\implies In\;One\;Hour,\;The\;Tank\;is\;filled\;by : (\frac{T}{30})}

\bf{\implies In\;30\;Hours,\;The\;Tank\;is\;filled\;by : (\frac{T}{30} \times 30)}

\bf{\implies In\;30\;Hours,\;The\;Tank\;is\;filled\;by : T}

Both Pipes fill the Tank Completely in 30 Hours

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