Question

plz give correct answer
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Answer 1

☯ GIVEN :-

• The age of Manthan is 9/11 of his brother's age.

• The age of Manthan's father is 23 years more than the age of Manthan.

• The average age of Manthan, Manthan's father and Manthan's brother is 27 years.

☯ TO FIND :-

• Manthan's age.

➲SOLUTION :-

• Let the age of Manthan's brother be x years.

• The age of Manthan is 9/11 of his brother's age.

• Then, the age of Manthan = x×9/11 = 9x/11 years.

• The age of Manthan's father is 23 years more than the age of Manthan.

• The age of Manthan's father = (9x/11)+23 years.

• The average age of Manthan, Manthan's father and Manthan's brother is 27 years.

We know that,

$\bigstar{ \underline{\boxed{ \ \red{ \tt{Average \: Age = \dfrac{Total \: sum \: of \: ages}{Total \: persons} }}}}} \bigstar$

Substituting the values :—

$\implies {\sf{Average \: Age = \dfrac{Total \: sum \: of \: ages}{Total \: persons}}}$

$\implies{\sf{27= \dfrac{x + \dfrac{9x}{11} + \bigg( \dfrac{9x}{11} + 23 \bigg) }{3}}}$

$\implies{\sf{27= \dfrac{x + \dfrac{9x}{11} + \bigg( \dfrac{9x +253 }{11 } \bigg) }{3}}}$

$\implies{\sf{27= \dfrac{x + \dfrac{9x}{11} + \dfrac{9x +253 }{11 } }{3}}}$

$\implies{\sf{27= \dfrac{ \dfrac{11x + 9x + 9x + 253}{11} }{3}}}$

$\implies{\sf{27= \dfrac{ \dfrac{29x+ 253}{11} }{3}}}$

$\implies{\sf{27 \times 3= \dfrac{29x + 253}{11} } }$

$\implies{\sf{81= \dfrac{29x + 253}{11} } }$

$\implies{\sf{81 \times 11= 29x + 253} }$

$\implies{\sf{891 - 253 =29x }}$

$\implies{\sf{638=29x }}$

$\implies \sf{ x = \cancel{ \dfrac{638 }{ 29}}}$

$\implies \underline{\huge {\boxed{\red{\bf{ x =22 }}}}}$

$\huge{\pink{\therefore}}$ Manthan's age = 22×9/11 = 18 years.

Answer 2

Answer:

GIVEN :-

The age of Manthan is 9/11 of his brother's age.

The age of Manthan's father is 23 years more than the age of Manthan.

The average age of Manthan, Manthan's father and Manthan's brother is 27 years.

☯ TO FIND :-

Manthan's age.

➲SOLUTION :-

Let the age of Manthan's brother be x years.

The age of Manthan is 9/11 of his brother's age.

Then, the age of Manthan = x×9/11 = 9x/11 years.

The age of Manthan's father is 23 years more than the age of Manthan.

The age of Manthan's father = (9x/11)+23 years.

The average age of Manthan, Manthan's father and Manthan's brother is 27 years.

Step-by-step explanation:

$We know that,</p><p></p><p>\bigstar{ \underline{\boxed{ \ \red{ \tt{Average \: Age = \dfrac{Total \: sum \: of \: ages}{Total \: persons} }}}}} \bigstar★ AverageAge=TotalpersonsTotalsumofages★</p><p></p><p>Substituting the values :—</p><p></p><p>\begin{gathered}\implies {\sf{Average \: Age = \dfrac{Total \: sum \: of \: ages}{Total \: persons}}} \\ \\ \end{gathered}⟹AverageAge=TotalpersonsTotalsumofages</p><p></p><p>\begin{gathered}\implies{\sf{27= \dfrac{x + \dfrac{9x}{11} + \bigg( \dfrac{9x}{11} + 23 \bigg) }{3}}} \\ \\\end{gathered}⟹27=3x+119x+(119x+23)</p><p></p><p>\begin{gathered} \implies{\sf{27= \dfrac{x + \dfrac{9x}{11} + \bigg( \dfrac{9x +253 }{11 } \bigg) }{3}}} \\ \\ \end{gathered}⟹27=3x+119x+(119x+253)</p><p></p><p>\begin{gathered}\implies{\sf{27= \dfrac{x + \dfrac{9x}{11} + \dfrac{9x +253 }{11 } }{3}}} \\ \\\end{gathered}⟹27=3x+119x+119x+253</p><p></p><p>\begin{gathered} \implies{\sf{27= \dfrac{ \dfrac{11x + 9x + 9x + 253}{11} }{3}}} \\ \\\end{gathered}⟹27=31111x+9x+9x+253</p><p></p><p>\begin{gathered}\implies{\sf{27= \dfrac{ \dfrac{29x+ 253}{11} }{3}}} \\ \\ \end{gathered}⟹27=31129x+253</p><p></p><p>\begin{gathered} \implies{\sf{27 \times 3= \dfrac{29x + 253}{11} } } \\ \\ \end{gathered}⟹27×3=1129x+253</p><p></p><p>\begin{gathered}\implies{\sf{81= \dfrac{29x + 253}{11} } } \\ \\ \end{gathered}⟹81=1129x+253</p><p></p><p>\begin{gathered}\implies{\sf{81 \times 11= 29x + 253} } \\ \\ \end{gathered}⟹81×11=29x+253</p><p></p><p>\begin{gathered}\implies{\sf{891 - 253 =29x }} \\ \\\end{gathered}⟹891−253=29x</p><p></p><p>\begin{gathered}\implies{\sf{638=29x }} \\ \\\end{gathered}⟹638=29x</p><p></p><p>\begin{gathered} \implies \sf{ x = \cancel{ \dfrac{638 }{ 29}}} \\ \\ \end{gathered}⟹x=29638</p><p></p><p>\implies \underline{\huge {\boxed{\red{\bf{ x =22 }}}}}⟹x=22</p><p></p><p>\huge{\pink{\therefore}}∴ Manthan's age = 22×9/11 = 18 years.</p><p></p><p>$