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Answered by
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Answer:
A. 26degree
B. 70degree
Answered by
1
Answer: for figure (a) 26 (b) 30
Step-by-step explanation: for (a):
in Δ ECD applying angle sum theorem
35° + 39° + ∠ECD = 180°
∴ ∠ECD = 180° - (74)
= 106°
Also ∠ECD = ∠ACB (Opposite angles)
Thus in ΔABC
x + 48 + 106 = 180
x = 180 - 154
x = 26°
part (b)
in ΔKLM
External angle is the sum of two opposite angles,
∴∠MKL = 105 - 35
= 70
Now in ΔFKH using same theorem
x = ∠FKL - ∠FHK
= 70 - 40
x = 30°
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