Question

plz give explanation also​

Answer 1

1) In the given figure

BC = EF = 5.3 cm

BA = ED = 4.2 cm

Angle A = Angle E = 60°

ACCORDING TO ABOVE REASONS AC = DF Therefore , ∆ABC IS congruent to ∆EDF

2) In the given figure

GK = HI ( parallel lines ) = 4.2 cm

GI = KH ( Parallel lines ) = 4.2 cm

Angle G = Angle G = 60°

Therefore', ∆ GKH is congruent to ∆GIH

3) In the given figure

KJ=QN = 3cm

KL = MQ = 4CM

According to above reasons

JL= MN

Therefore, ∆KLG IS CONGRUENT TO ∆MON

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