Math, asked by siddharthkadam3018, 1 year ago

plz give fast answer

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Answers

Answered by sololomon0015
0

Answer:


Step-by-step explanation:

John takes 10 days to complete one work

Therefore in one day he completes 1/10

Charlie takes 15 days

Hence one day he completes 1/15

Hence

When both work together for one day the work completed is

1/10 + 1/15

= (15 + 10)/10×15

=25/150

=1/6

Implies they take 6 days



Answered by siddhartharao77
0

Answer:

Option(A)

Step-by-step explanation:

(i)

John can do a piece of work in 10 days.

Amount of work-done by John in 1-day = (1/10).


(ii)

Charles can finish a work in 15 days.

Amount of work done by Charles in 1-day = (1/15).


(iii)

Total work done by (John + Charles) in 1-day = (1/10) + (1/15)

= (3 + 2)/30

= 5/30

= 1/6.


Therefore, they will finish the work in 6 days.


Hope it helps!

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