plz give fast answers/4. Diameter of a circle is 40cm and distance of the chord from centre of the circle is 12 cm
Find the length of the chord.
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Diameter of the circle =40 cm
∴ Radius (r) of the circle =240=20 cm
Let AB be a chord (length = 20 cm) of the circle.
In △OAB, OA = OB = Radius of circle = 20 cm
Also, AB = 20 cm
Thus, △OAB is an equilateral triangle.
∴θ=60∘=3π radian
We know that in a circle of radius r unit, if an arc of length I unit subtends an angle θ radian at the centre, then θ=rl
∴3π=20arc AB⟹arc AB=320π cm
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