Physics, asked by Anonymous, 1 month ago

plz give me a answer of this question ​

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Answered by rakshith0806
1

Explanation:

(i) C2,C3,C4 are parallel

Cp=2+2+2=6 microfarad

now C1,Cp,C5 are in series

1/Cs=1/2+1/6+1/2

Cs=6/7 microfarad

(ii)U=1/2CV^2=1/2×6/7×10^-6×49= 21 microjoules

Q=CV=6/7×10^-6×7=6 microcoulomb

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