Question

plz give me ans as soon as possible
,icse class 9th ,
mera paper Monday ko ha​

Answer 1

I hope this will help you dear..

Always stay safe and stay healthy..

Answer 2

ICSE class 10th student here..

I think the given question is from selina concise mathematics..

My preboard are also starting from Monday i.e 1st March..

${\huge{\star{\underbrace{\tt{\red{Answer}}}}}}{\huge{\star}}$

Given :

• Side a = 18cm
• Side b = 24cm
• Side c = 30cm

To find :

• Area of triangle.

Solution :

By heron's formula

${\boxed{\star \sf \ Area \ of \ triangle \ = \ \sqrt{s(s - a)(s - b)(s -c )} }}$

here,

• s = semiperamater
• a = first side
• b = second side
• c = third side

Now ,

${\sf{\large \ Semiperamater \ = \ \frac{a + b + c}{2} }}$

${\sf{\implies \ Semiperamater \ = \ \frac{18 + 24 + 30}{2}}}$

${\sf{\implies \ Semiperamater \ = \ \frac{72}{2}}}$

${\sf{\implies \ Semiperamater \ = \ 36cm}}$

__________________

${\sf{\large { Area \ = \ \sqrt{s(s - a)(s - b)(s -c )}}}}$

${\sf{\implies \ Area \ = \ \sqrt{36(36 - 24)(36 - 18)(36 - 30)} }}$

${\sf{\implies \ Area \ = \ \sqrt{36 \times 12 \times 18 \times 6} }}$

${\sf{\implies \ Area \ = \ \sqrt{(6 \times 6) \times (6 \times 2) \times (6 \times 3) \times (2 \times 3)} }}$

${\sf{\implies \ Area \ = \ \sqrt{2 \times 3 \times 2 \times 3 \times 2 \times 3 \times 2 \times 2 \times 3 \times 3 \times 2 \times 3} }}$

${\sf{\implies \ Area \ = \ \sqrt{2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 3 \times 3 \times 3 \times 3 \times 3 \times 3} }}$

${\sf{\implies \ Area \ = \ \times 2 \times 2 \times 2 \times 3 \times 3 \times 3}}$

${\sf{\implies \ Area \ = \ 216{cm}^{2} }}$

Hence the area of triangle is 216cm².

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Hope it's help ⚓⚓

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