Question

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Answer 1

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Answer 2

We know that, $a^{2} -b^{2} = (a+ b)(a-b)$

Therefore, $(4 +\sqrt{3} )(4 - \sqrt{3} ) = (4)^{2} - (\sqrt{3} )^{2}$

Thus, $(4 +\sqrt{3} )(4 - \sqrt{3} ) = (16 - 9) = 7$

As "7" is a rational number, $(4 +\sqrt{3} )(4 - \sqrt{3} )$ is also rational.

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