plz give me ans of this qus. 2x^2-x+1/8=0 plzz hurryyy up
Answers
Answered by
4
2x^2 - x + 1/8 = 0.
16 x^2 - 8x + 1 = 0
16 x^2 - 4x - 4x +1 = 0
4x ( 4x - 1 ) - 1 ( 4x - 1 ) = 0
( 4x - 1 ) ( 4x - 1 ) = 0
x = 1 /4, 1 /4
16 x^2 - 8x + 1 = 0
16 x^2 - 4x - 4x +1 = 0
4x ( 4x - 1 ) - 1 ( 4x - 1 ) = 0
( 4x - 1 ) ( 4x - 1 ) = 0
x = 1 /4, 1 /4
Anonymous:
In 2nd line, multiply the equation by 8.
ok thanks
As we take LCM, similar to that.
ok i understand
And the common 8 in the denominator will be multiplied to 0, so it will become 0.
OK.
okkk thanx
x=-b+-√b^2-4ac/2a formula se kiya h
quardatic equation formula se h
Answered by
0
2x^2-x+1/8=0
so
x=-1/4
so
x=-1/4
bhai ans wrong hai plzz give us write ans
+1/4 hoga sorry bhai
pura calculation bata bhai
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