Math, asked by manjotgill6227, 1 year ago

plz give me Answer ............?

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Answered by ilikeme
0

Given AP is 11,8,5,2.................

To check whether -150 is a term of the given AP,

Let us assume that -150 is the nth term of the AP

a_{n} = - 150

                   also a = 11

                           d = -3

now

            a_{n} = a + ( n - 1)d

                             -150 = 11 + (n-1)× -3

                              - 161 = (n-1) × -3

                           - 161/-3 = n-1

                          161/3 + 1 = n

                               164/3 = n

                                 ∴ n = 54.33

But n cannot be decimal

           hence - 150 is not a term of the given AP


               

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