plz give me answer........
A , B and C can complete a work in 5 days. if A and C can complete the same work in 7 1/2 days and A alone in 15 days, then in how many days can B and C finish the work.
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Answered by
0
Answer:
let
A and B done work in 5 days
A and C done work in 7 half days
for an average
5day/2 and 7.5day/2
2.5day + 3.75day
6.25day
6 1/4 day taken B and C to finish work
i hope it helpfull to you
Answered by
3
Step-by-step explanation:
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↪ A+B= 15
A+ B+C= 8
A+B= 15A+ B+C= 8
Total work= 25*8= 120
So, (A+B+c)= 15unit/day,
and (B+c)= 8 unit/day.
Hence, C=7 unit/day;
so, C= 120/7 days.
And, A+C= (B+C)+2 days, since tot. work is 120,this means A+C= 10 days,
and B+C= 12 days (as both A+C,
and B+C have to be the factor of 120.
So, A+C does= 120/10= 12 unit/day; so, A=12-7=5 unit/day= Alone in 40 days.
B= 24 days.
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