Question

plz give me answer as possible​

Answer 1

Theres a equation.

A(inverse) = [adjoint(A)]/[Determinat(A)]

Determinat (A) =1(1-(-3)) -(-1)(2-(-3)) +1(2-1)

=4+5+1=10.

and given Matrix B has a coefficient of 1/10.

Meaning. B= [adjoint(A)]/[10] =[adjoint of A]/[Determinant of A]

Since determinat is 10. we can find the value of Alpha by comparing it with adjoint A.

alpha's position in B is (2,3).

i.e (2,3) in adjoint A.

a(2,3) in adjoint A is equal to.

negative determinant of (1,1)(1,2) (3,1)(3,2)

ie. = -[1(1) - (1)(-1)]=-[1+1]=-2.

and the answer is -2.

Yes!

Hope it helps...

Regards,

Leukonov/Olegion.