Question

plz give me answer fast​

Answer 1

$\color{darkblue}\underline{\underline{\sf Given-}}$

• Object is placed at Distance (u) = -10cm
• Focal length (f) = -20cm

$\color{darkblue}\underline{\underline{\sf To \: Find-}}$

• Ray Diagram
• Image Distance (v)
• Characteristics of Image .

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$\color{darkblue}\underline{\underline{\sf Formula \: Used-}}$

✏ Mirror's Formula

$\color{violet}\blacksquare\underline{\boxed{\sf \dfrac{1}{f}=\dfrac{1}{v}+\dfrac{1}{u}}}$

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$\implies{\sf -\dfrac{1}{20}=\dfrac{1}{v}+\left(-\dfrac{1}{10}\right)}$

$\implies{\sf -\dfrac{1}{20}=\dfrac{1}{v}-\dfrac{1}{10}}$

$\implies{\sf \dfrac{1}{v}=-\dfrac{1}{20}+\dfrac{1}{10} }$

$\implies{\sf \dfrac{1}{v}=\dfrac{10+(-20)}{-20×10} }$

$\implies{\sf \dfrac{1}{v}=\dfrac{-10}{-200}}$

$\color{red}\implies{\sf v=+20cm }$

Image is formed at $\color{red}{\sf +20cm}$

$\underline{\sf Characteristics \; of \; image -}$

• Image is formed behind the mirror
• Image size is large
• Image is virtual

Refer to the attachment for the Diagram.