Math, asked by khanrehana20525, 11 months ago

plz give me answer i will marks as brainlist answers give me answer fast ?​

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Answers

Answered by Iashimaj6
0

Answer:

Given:

1. AB ll SR

2. PQRS is a rectangle

To Prove:

TS^2 + TQ^2 = TP^2 + TR^2

Proof:

AT^2 + AS^2 = TS^2

BQ^2 + BT^2 = TQ^2

TS^2 + TQ^2 = AT^2 + AS^2 + BQ^2 + BT^2

TS^2 + TQ^2 = AT^2 + AP^2 + BT^2 + BR^2 (AB ll SR, Therefore, AP = BQ and AS = BR)

Thus,

TS^2 + TQ^2 = TP^2 + TR^2 (TP^2 = AT^2 + AP^2, TR^2 = BT^2 + BR^2)

Hence, proved

Please mark as brainliest

Answered by kavitasingh1234
0

Answer:

not knowing answer very hard..... but tried.....

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