Math, asked by njha28778, 8 months ago

plz give me answer in notebook.... don't give wrong answer​

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Answers

Answered by arvindhan14
1

Answer:

a. (a + b + c)

b. 3(a + b + c)

c. 111

Step-by-step explanation:

The numbers are :

1) 100a + 10b + c

2) 100b + 10c + a

3) 100c + 10a + b

The sum of numbers is:

100a + 10b + 10c + 100b + 10c + a + 100c + 10a + b

= 111a + 111b + 111c

= 111(a + b + c)

a. When 111(a + b + c) is divided by 111 :

111(a + b + c) / 111 = (a + b + c)

b. When 111(a + b + c) is divided by 37 :

111(a + b + c) / 37 = 3(a + b + c)

c. When 111(a + b + c) is divided by (a + b + c) :

111(a + b + c) / (a + b + c) = 111

Hope this helps.

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