plz give me answer of given above
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By the formula of area of triangle in ∆ABC
1/2[ x1 (y2-y3) +x2 (y3-y-1) +x3 (y1-y2)]..........
1/2[-2 ( 0-b) +a(b+1) +4 (-1+0)]
1/2[ -2(b)+a(b+1) +4(-1)]
1/2[ -2b+ab+a-4]
1/2[ x1 (y2-y3) +x2 (y3-y-1) +x3 (y1-y2)]..........
1/2[-2 ( 0-b) +a(b+1) +4 (-1+0)]
1/2[ -2(b)+a(b+1) +4(-1)]
1/2[ -2b+ab+a-4]
suyash411:
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