Math, asked by rwnu, 1 year ago

plz give me answer of question no 31 both

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Answers

Answered by Idiotic7leverage
1
area of shaded Region= Area of square - Area of the four quadrant
D=14 R= D/2= 7
Area of square = side^2
Area of the quadrat = 22/7x r square
14^2-22/7x(7^2)
196-154
42square cm
£££££¥¥¥¥¥question no.2¥¥¥¥¥₩₩₩
boundary of all= sum of two small semicircle and big circle perimeter of small circle =2(3.14x5)+(3.14×10)
=31.40+31.4
=62.80
###$$$$second part $$$##
area of shaded Region =area of semi bigger circle-area of semi smaller circle + area of smaller semi circle
area of shaded region =area of bigger semi circle
=3.14xr^2
=3.14×10×10
=314 cm^2

rwnu: ur answer is wrong
Idiotic7leverage: how
rwnu: look at my question again
Idiotic7leverage: i have seen can u please clear what is wrong
rwnu: in first question we have to find the area of shaded region..u r not finding the area of four circles..it us also shaded
Answered by AMAYTRIPATHI
0
hi friend
here's your answer looking for

check it out in image

hope you are satisfied with my answer
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