Question

plz give me answer of this​

Answer 1

In cyclic quadrilateral PQRS, ∠Q = 70°

$\therefore ∠Q + ∠S = 180° ....( Opposite \: angles \: of \: cyclic \: quadrilateral \: are \: supplementary)$

$\sf \therefore \: 70^{ \circ} + ∠S = 180 {}^{ \circ}$

$\sf \therefore \: ∠S = 180 {}^{ \circ} - 70 {}^{ \circ}$

$\boxed{ \sf \therefore ∠S = 110 {}^{ \circ} }$

Answer 2

Answer:

110*

Step-by-step explanation:

In cyclic quadrilateral PQRS, ∠Q = 70°

\therefore ∠Q + ∠S = 180° ....( Opposite \: angles \: of \: cyclic \: quadrilateral \: are \: supplementary)∴∠Q+∠S=180°....(Oppositeanglesofcyclicquadrilateralaresupplementary)

\sf \therefore \: 70^{ \circ} + ∠S = 180 {}^{ \circ}