Question

plz give me answer of this question​

Answer 1

Answer:

We know that diagonals of parallelogram bisect each other.

So ABCD is a parrallelogram and AC and BD are diaginal

Therefore, O is the mid-point of AC and BD.

BO is the median in ∆ABC. Therefore, it will divide it into two triangles of equal areas.

∴ Area (∆AOB) = Area (∆BOC) ... (1)

In ∆BCD, CO is the median.

Step-by-step explanation:

∴ Area (∆BOC) = Area (∆COD) ... (2)

Similarly, Area (∆COD) = Area (∆AOD) ... (3)

From Equations (1), (2), and (3), we obtain

Area (∆AOB) = Area (∆BOC) = Area (∆COD) = Area (∆AOD)

Therefore, the diagonals of a parallelogram divide it into four triangles of equal area.

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