plz give me answer quickly
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L.H.S = tan-1(1/4)+tan-1(2/9) = tan-1(1/4+2/9)/(1-1/4*2/9) = tan-1(1/2) = 1/2*2tan-1(1/2)
= 1/2cos-1(1-1/4)/(1+1/4) = 1/2cos-1(3/5)
I hope it's helps you
your question is wrong there is tan inverse 2/9
= 1/2cos-1(1-1/4)/(1+1/4) = 1/2cos-1(3/5)
I hope it's helps you
your question is wrong there is tan inverse 2/9
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