Plz give me answers for these questions
it's very urgent
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Hey mate!
Here's your answer!!
The quadrilateral ABCD is divided into two triangles. ABD and BCD.
ABD is a right angle triangle.
Area = 1/2 AB × AD as angle A is 90, AB is the altitude and AD is the base.
= 1/2 × 18 × 24 = 216 cm²
BC² = AB² + AD² => BC = 30 cm
BCD triangle
s = semi perimeter = 60 cm
Area = √(60 × 30 × 20 × 10 ) = 600 cm²
Total area = 816 cm²
Here's your answer!!
The quadrilateral ABCD is divided into two triangles. ABD and BCD.
ABD is a right angle triangle.
Area = 1/2 AB × AD as angle A is 90, AB is the altitude and AD is the base.
= 1/2 × 18 × 24 = 216 cm²
BC² = AB² + AD² => BC = 30 cm
BCD triangle
s = semi perimeter = 60 cm
Area = √(60 × 30 × 20 × 10 ) = 600 cm²
Total area = 816 cm²
Garry252:
thanks
sir did u answered another question??
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