plz give me answers in marathi translation
Answers
Answer:
Your input 0.8,1.2,1.6,2 appears to be an arithmetic sequence
Find the difference between the members
a2-a1=1.2-0.8=0.4
a3-a2=1.6-1.2=0.4
a4-a3=2-1.6=0.4
The difference between every two adjacent members of the series is constant and equal to 0.4
General Form: an=a1+(n-1)d
an=0.8+(n-1)0.4
a1=0.8 (this is the 1st member)
an=2 (this is the last/nth member)
d=0.4 (this is the difference between consecutive members)
n=4 (this is the number of members)
Sum of finite series members
The sum of the members of a finite arithmetic progression is called an arithmetic series.
Using our example, consider the sum:
0.8+1.2+1.6+2
This sum can be found quickly by taking the number n of terms being added (here 4), multiplying by the sum of the first and last number in the progression (here 0.8 + 2 = 2.8), and dividing by 2:
n(a1+an)2
4(0.8+2)
2
The sum of the 4 members of this series is 5.6
This series corresponds to the following straight line y=0.4x+0.8
Finding the nthelement
a1 =a1+(n-1)*d =0.8+(1-1)*0.4 =0.8
a2 =a1+(n-1)*d =0.8+(2-1)*0.4 =1.2
a3 =a1+(n-1)*d =0.8+(3-1)*0.4 =1.6
a4 =a1+(n-1)*d =0.8+(4-1)*0.4 =2
a5 =a1+(n-1)*d =0.8+(5-1)*0.4 =2.4
a6 =a1+(n-1)*d =0.8+(6-1)*0.4 =2.8
a7 =a1+(n-1)*d =0.8+(7-1)*0.4 =3.2
a8 =a1+(n-1)*d =0.8+(8-1)*0.4 =3.6
a9 =a1+(n-1)*d =0.8+(9-1)*0.4 =4
a10 =a1+(n-1)*d =0.8+(10-1)*0.4 =4.4
a11 =a1+(n-1)*d =0.8+(11-1)*0.4 =4.8
a12 =a1+(n-1)*d =0.8+(12-1)*0.4 =5.2
a13 =a1+(n-1)*d =0.8+(13-1)*0.4 =5.6
a14 =a1+(n-1)*d =0.8+(14-1)*0.4 =6
a15 =a1+(n-1)*d =0.8+(15-1)*0.4 =6.4
a16 =a1+(n-1)*d =0.8+(16-1)*0.4 =6.8
a17 =a1+(n-1)*d =0.8+(17-1)*0.4 =7.2
a18 =a1+(n-1)*d =0.8+(18-1)*0.4 =7.6
a19 =a1+(n-1)*d =0.8+(19-1)*0.4 =8
a20 =a1+(n-1)*d =0.8+(20-1)*0.4 =8.4
a21 =a1+(n-1)*d =0.8+(21-1)*0.4 =8.8
a22 =a1+(n-1)*d =0.8+(22-1)*0.4 =9.2
a23 =a1+(n-1)*d =0.8+(23-1)*0.4 =9.6
a24 =a1+(n-1)*d =0.8+(24-1)*0.4 =10
a25 =a1+(n-1)*d =0.8+(25-1)*0.4 =10.4
a26 =a1+(n-1)*d =0.8+(26-1)*0.4 =10.8
a27 =a1+(n-1)*d =0.8+(27-1)*0.4 =11.2
a28 =a1+(n-1)*d =0.8+(28-1)*0.4 =11.6
a29 =a1+(n-1)*d =0.8+(29-1)*0.4 =12
Sorry It's in English don't know to answer in marathi
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