Question

plz give me correct and complete answer otherwise I will report your answer both questions​

Answer 1

Step-by-step explanation:

sorry bhai....../ sis.... .

I want inbox power

Answer 2

Answer:

$\\ x ^{2} + 11x + 18 \\ \\ x ^{2} + 9x + 2x + 18 \\ \\ x(x + 9) + 2(x + 9) \\ \\ (x + 2)(x + 9) \\ \\ x = - 2 \: \: x = - 9 \\ \\ so \: the \: zeroes \: of \: p(x) are \: - 2 \: and \: - 9 \\ \\ <u>sum \: of \: zeroes = ( - 2 + ( - 9)) </u>\\ \\ \: \: \: \: = - 11 \\ \\ <u>product \: of \: zeroes = </u> - 2 \times - 9 \\ \: \: \: \: \: \: = 18 \\ \\ b)we \: have \: \\ \\ 2x ^{2} + x - 6 \\ \\ 2x ^{2} + 4x - 3x - 6 \\ \\ 2x(x + 2) - 3(x + 2) \\ \\ (2x - 3)(x + 2) \\ \\ x = \frac{3}{2} \: \: x = - 2 \\ \\ so \: the \:<u> zeroes \: of \: f(x) \: are</u> \<u>frac{3}{2} and \: - 2 \</u>\ \\ sum \: of \: zeroes \: = \: \frac{3}{2} + - 2 \\ = \frac{ - 1}{2} \\ \\ product \: of \: zeroes = \frac{3}{2} \times - 2 \\ \\ = - 3$