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Answers
Step-by-step explanation:
Question 1) Shekar drives his car at a constant speed . If he travels 8 km in 10 minutes , o ong will he take to travel 36 km ?
Answer 1) If he travels 8km in 10min, how long will he travel 36km? SO HE 36 KM TRAVELS IN 45 MINS. 10 minutes because the car is moving at a constant speed . So the time taken by the car will not change .
Question 2) Shaili sells 50 tickets for the school raffle and receives a commission of rupees 5 Sonia sells 96 ticket for the same raffle what is her Commission
Answer 2) As , 60/ 5= 12 96/12 = 8 , So Sonia commission was ₹ 8
Question 3) last month Roni sold rupees 35000 watt of quiet and got a commission of rupees 10050 if he sells rupees 42000 worth of this month what will be his commission
Answer 3) Rohit sold toys of amount = Rs.3500
Commission = Rs.1050
Rate of commission =\frac{1050}{3500} \times 100 = 30 \%
3500
1050
×100=30%
Now Rohit sold toys of amount = Rs.4200
So, His commission = 30\% \times 420030%×4200
His commission =\frac{30}{100} \times 4200=Rs.1260
100
30
×4200=Rs.1260
Hence His commission will be Rs.1260
Question 4) the interest on rupees 30000 for one year is 210 what is the interest on 45000 for years if one wants to get an interest for 700 what should be the
Answer 4) Rs. 315 as SI and Rs.10000 as principal.
Step-by-step explanation:
Since we have given that
Sum = Rs. 3000
S.I. = Rs. 210
Time = 1 year
So, it becomes,
\begin{gathered}210=\dfrac{3000\times R\times 1}{100}\\\\\dfrac{210}{30}=R\\\\7\%=R\end{gathered}
210=
100
3000×R×1
30
210
=R
7%=R
If sum = Rs. 4500
Then, interest would
\begin{gathered}SI=\dfrac{4500\times 7\times 1}{100}\\\\SI=315\end{gathered}
SI=
100
4500×7×1
SI=315
Now, interest = Rs. 700
So, it becomes,
\begin{gathered}700=\dfrac{P\times 7\times 1}{100}\\\\100\times 100=P\\\\P=Rs.\ 10000\end{gathered}
700=
100
P×7×1
100×100=P
P=Rs. 10000
Hence, Rs. 315 as SI and Rs.10000 as principal.
# learn more:
13. 45 minutes.
14. ₹8
15. ₹1260
16. 10000
are correct answer.
please mark as brainliest answer.
I hope this helps