Question

plz give me correct answer. ​

Answer 1

Step-by-step explanation:

Given expression is

1+sin2A

−

1−sin2A

1+sin2A

+

1−sin2A

=

(cosA+sinA)

2

−

(cosA−sinA)

2

(cosA+sinA)

2

+

(cosA−sinA)

2

=

∣cosA+sinA∣−∣cosA−sinA∣

∣cosA+sinA∣+∣cosA−sinA∣

=

cosA+sinA−(cosA−sinA)

cosA+sinA+cosA−sinA

(∵−

4

π

<A<

4

π

and in this interval cosA>sinA)

=

2sinA

2cosA

=cotA when ∣tanA∣<1 and ∣A∣ is acute.

Answer 2

Answer:

I'm just 6th grade

Step-by-step explanation:

btw ur hand writing is very beautiful ❤️