Question

plz give me correct answer plz.

don't samp..
only for correct answer OK.... ​

Answer 1

$given \: that -$

ABCD is a ||gm , linesegment AE and CF bisects <A and <C .

$we \: have \:to \: proof$

AE || CF

Proof,

(1) <A = <C

=> 1/2 <A = 1/2 <C

=> <1 = <2

(2) AB||CD and CY is the transversal

So, <2=<3.

From equation (1) and (2) we have ,

=> <1 = <2

Transversal AB intersect AE and CF at A and F such that ,

=> <1 = <3

= AE||CF

I hope its help you..

Answer 2

Answer:

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