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NewBoy123:
D is right answer....
bhkk
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0.2 kg m sec-1
impulse =mv-mu
find v=slope = 4-0/2-0 = 4/2= 2
mv = 0.2
mu=0
so impulse = 0.2
impulse =mv-mu
find v=slope = 4-0/2-0 = 4/2= 2
mv = 0.2
mu=0
so impulse = 0.2
iska matlabb velocity at 2 sec = 0
abb 0-2 sec walee part mee x-t graph ka slope linear orr positive hai with slope = 2
matlabb. u = 2. and v = 0
2 sec ke baad hai na ...agar ye straight line na hoti toh aap toh +ive ans de te
impulse = m(v-u) = 0.1(0-2) =- 0.2 ans
sry aap u ko 2 kyun maan rhe ho mujhe ni samjh aa rha
matlab agar graph same linear hii raha jaisa 0-2 sec mee hai
okk koi ni kal dekti hun iska ans
nahi ans -0.2 sahi hai
waise kahi kal hi to exam nahi hai tumhara jee mains walaa
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hii mein anjali hauare you
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