Question

plz give me solution....​

Answer 1

Answer:

As we know,

QP=QR ( Given- Q is the equidistant from P and R)

QP=√(0-5)^2+(1-[-3])^2

=√(5)^2+(4)^2

=√25+16

=√41

QR=√(0-x)^2+(1-6)^2

=√x^2+(-5)^2

=√x^2+25

Now as per the given condition,

√41=√x^2+25

Now on squaring both sides,

41=x^2+25

41-25=x^2

16=x^2

x=√16=4