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Anonymous:
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4
1
= -----------------------------
√6 + √5 - √11
By multiplying the numerator and denominator by { ( √6 + √5 ) + √11 }.
= 1 { ( √6 + √5 ) + √11 } / { ( √6 + √5 ) - √11 } { ( √6 + √5 ) + √11 }.
= { ( √6 + √5 ) + √11 } / { ( √6 + √5 )^2 - ( √11 )^2 }
= { ( √6 + √5 ) + √11 } / { 6 + 5 + 2√30 - 11 }
= { ( √6 + √5 ) + √11 } / { 11 - 11 + 2√30 }
= { ( √6 + √5 ) + √11 } / ( 2√30 )
{ ( √6 + √5 ) + √11 }
= -------------------------------------
2√30
Now by multiplying numerator and denominator by √30 .
= ( √6 + √5 + √11 ) √30 / ( 2√30 ) ( √30 )
6√5 + 5√6 + √330
= -------------------------------------
60
= -----------------------------
√6 + √5 - √11
By multiplying the numerator and denominator by { ( √6 + √5 ) + √11 }.
= 1 { ( √6 + √5 ) + √11 } / { ( √6 + √5 ) - √11 } { ( √6 + √5 ) + √11 }.
= { ( √6 + √5 ) + √11 } / { ( √6 + √5 )^2 - ( √11 )^2 }
= { ( √6 + √5 ) + √11 } / { 6 + 5 + 2√30 - 11 }
= { ( √6 + √5 ) + √11 } / { 11 - 11 + 2√30 }
= { ( √6 + √5 ) + √11 } / ( 2√30 )
{ ( √6 + √5 ) + √11 }
= -------------------------------------
2√30
Now by multiplying numerator and denominator by √30 .
= ( √6 + √5 + √11 ) √30 / ( 2√30 ) ( √30 )
6√5 + 5√6 + √330
= -------------------------------------
60
Answered by
2
Solution for question 4.
Given , x = 9 + 4√5.
So, 1/x = 1 / ( 9 + 4√5 ).
By multiplying numerator and denominator by ( 9 - 4√5 ).
= 1 ( 9 - 4√5 ) / ( 9 + 4√5 ) ( 9 - 4√5 )
= ( 9 - 4√5 ) / { ( 9 )^2 - ( 4√5 )^2 } [ ( a + b ) ( a - b ) = a^2 - b^2 ]
= ( 9 - 4√5 ) / { 81 - 80 }
= ( 9 - 4√5 ).
Now .
= √x + 1/√x
By substituting the value of x and 1/x.
= √( 9 + 4√5 ) + √( 9 - 4√5 )
By squaring and then rooting it.
= √[{ √( 9 + 4√5 ) + √( 9 - 4√5 ) }^2 ]
= √[ { 9 + 4√5 + 9 - 4√5 + 2 ( 9 + 4√5 ) ( 9 - 4√5 ) ]
= √ [ 18 + 2 { ( 9 )^2 - ( 4√5 )^2 } ]
= √ [ 18 + 2 { 81 - 80 } ]
= √ [ 18 + 2 ]
= √20
= 2√5.
Given , x = 9 + 4√5.
So, 1/x = 1 / ( 9 + 4√5 ).
By multiplying numerator and denominator by ( 9 - 4√5 ).
= 1 ( 9 - 4√5 ) / ( 9 + 4√5 ) ( 9 - 4√5 )
= ( 9 - 4√5 ) / { ( 9 )^2 - ( 4√5 )^2 } [ ( a + b ) ( a - b ) = a^2 - b^2 ]
= ( 9 - 4√5 ) / { 81 - 80 }
= ( 9 - 4√5 ).
Now .
= √x + 1/√x
By substituting the value of x and 1/x.
= √( 9 + 4√5 ) + √( 9 - 4√5 )
By squaring and then rooting it.
= √[{ √( 9 + 4√5 ) + √( 9 - 4√5 ) }^2 ]
= √[ { 9 + 4√5 + 9 - 4√5 + 2 ( 9 + 4√5 ) ( 9 - 4√5 ) ]
= √ [ 18 + 2 { ( 9 )^2 - ( 4√5 )^2 } ]
= √ [ 18 + 2 { 81 - 80 } ]
= √ [ 18 + 2 ]
= √20
= 2√5.
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